Solve the following pair of linearequations by elimintion method3x+2y-

1.	Solve the following pair of linearequations by elimintion method3x+2y-2=0; 2x+ 5y +6=0
Answer» Step-by-step explanation: $\sf 3x + 2y - 2 = 0$ $\sf 2x + 5y + <klux>6</klux> = 0$ $\text{Writing the <klux>EQUATIONS</klux> in their standard form,}$ 3x + 2y - 2 = 0 3x + 2y = 2 2x + 5y + 6 = 0 2x + 5y = - 6 $\sf 3x + 2y = 2$ $\sf 2x + 5y = -6$ Let's eliminate x . Multiplying the first eq. by 2 and 2nd eq. by 3 to make the coefficients of x same in both eq. $\sf 2(3x+2y=2)$ $\sf 3(2x + 5y = -6)$ (Subtracting the equations will CHANGE the signs in each term) $\sf \: 6x + 4y = 4$ (-) $\sf \underline{6x (-)+ 15y = (-)-18}$ -11y = 22 $\boxed{\sf y = -2}$ $\sf 3x + 2y=2$ $\sf 3x + 2(-2) = 2$ $\sf \implies 3x-4=2$ $\sf \implies 3x = 4+2$ $\sf \implies 3x = 6$ $\boxed{ \sf x=2}$ Hope it helps.