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Solve the following pair of linearequations by Substitution method3ax+2by-4-11=0; 2ax-3by+I0=0 |
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Answer» Answer: 3ax+2by-4-11=0 3ax+2by-15=0 1ST eq 2ax-3by+10=0 2ND eq both multiply eq 1st by 2 and eq 2nd by 3 6ax+4by=30 6ax-9by=-30 (-) (+) (+) 13by=60 by=60/13 by=60/133ax+2(60/13)=15 3ax+120/13=15 3ax+120=195 3ax=195-120 3ax=75 ax=25PLEASE MARK ME BRAINLIESTStep-by-step EXPLANATION: |
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