1.

Solve the following pair of linearequations by Substitution method3ax+2by-4-11=0; 2ax-3by+I0=0​

Answer»

Answer:

3ax+2by-4-11=0

3ax+2by-15=0 1ST eq

2ax-3by+10=0 2ND eq

both multiply eq 1st by 2 and eq 2nd by 3

6ax+4by=30

6ax-9by=-30

(-)   (+)       (+)

      13by=60

       by=60/13

        by=60/13

3ax+2(60/13)=15

3ax+120/13=15

3ax+120=195

3ax=195-120

3ax=75

ax=25

PLEASE MARK ME BRAINLIEST

Step-by-step EXPLANATION:



Discussion

No Comment Found

Related InterviewSolutions