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Solve the following quadratic equation by applying the quadratic formula`p^2x^2+(p^2-q^2)x-q^2=0`

Answer» `x = (-(p^2 - q^2) +- sqrt((p^2- q^2)^2 + 4p^2q^2))/(2p^2) `
`= (q^2 - p^2 +- sqrt(p^4 + q^4-2p^2q^2 + 4p^2q^2))/(2p^2)`
`= (q^2 - p^2 +- sqrt(p^4 + q^2 + 2p^2q^2))/(2p^2)`
`= (q^2 - p^2 +- (p^2 + q^2))/(2p^2)`
`x = (q^2 - p^2 + p^2 + q^2)/(2p^2)`
and `x= (q^2 - p^2 - p^2 - q^2)/(2p^2)`
so, `x= q^2 /p^2 and x= -1`
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