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Solve the following quadratic equation by factorisation:3y^2-y-10=0 |
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Answer» ==> 3y² - y - 10 = 0 ==> 3y² - (6-5)y - 10 = 0 ==> 3y(y - 2) +5 (y - 2) = 0 ==> ( 3y + 5 ) ( y - 2 ) = 0 ==> 3y + 5 = 0 ==> 3y = -5 ==> y = -5/3 either ==> y - 2 = 0 ==> y = 2 |
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