1.

Solve the following quadratic equation correct two decimal placesx²=3(12-x)​

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Step-by-step EXPLANATION:

\huge \bold{Answer:}

\bold{=>x²=3(12-x)} \\

\bold{=>x² + 3x-36=0}

\\ \bold{ = > x = \frac{ - 3 ± 3\sqrt{17} } { 2}}

\bold{=>x=4.68 \ \: or \: \: x=-7.68}

\bold{This \: is \: the \: correct \: answer .}


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