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Solve the following using laws of exponent. a) (-5/9)-² × (-3/5)-³ × (3/5)^-0b) {(-3/7)²}-³c) {(-7/9)-³ × (-9/7)-³}÷(-7/9)-³d) (5-² × 2-²) × 10²e) (-3/2)-⁴ × (-3/2)f) {(-1/3)-⁴ ÷ (-1/3)^-5}³Please help me. |
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Answer» Here are some solved examples on exponents using the laws of exponents.1. EVALUATE the exponent:(i) 5-3(ii) (1/3)-4(iii) (5/2)-3(iv) (-2)-5(v) (-3/4)-4We have:(i) 5-3 = 1/53 = 1/125(ii) (1/3)-4 = (3/1)4 = 34 = 81Here are some solved examples on exponents using the laws of exponents.1. Evaluate the exponent:(i) 5-3(ii) (1/3)-4(iii) (5/2)-3(iv) (-2)-5(v) (-3/4)-4We have:(i) 5-3 = 1/53 = 1/125(ii) (1/3)-4 = (3/1)4 = 34 = 81Step-by-step explanation:Solution:(-2/7)-4 × (-5/7)2= (7/-2)4 × (-5/7)2= (-7/2)4 × (-5/7)2 [Since, (7/-2) = (-7/2)]= (-7)4/24 × (-5)2/72= {74 × (-5)2}/{24 × 72 } [Since, (-7)4 = 74]= {72 × (-5)2 }/24= [49 × (-5) × (-5)]/16= 1225/163. Evaluate: (-1/4)-3 × (-1/4)-2Solution:(-1/4)-3 × (-1/4)-2= (4/-1)3 × (4/-1)2= (-4)3 × (-4)2= (-4)(3 + 2)= (-4)5= -45= -1024.4. Evaluate: {[(-3)/2]2}-3Solution:{[(-3)/2]2}-3= (-3/2)2 × (-3)= (-3/2)-6= (2/-3)6= (-2/3)6= (-2)6/36= 26/36= 64/7295. Simplify:(i) (2-1 × 5-1)-1 ÷ 4-1(ii) (4-1 + 8-1) ÷ (2/3)-1Solution:(i) (2-1 × 5-1)-1 ÷ 4-1= (1/2 × 1/5)-1 ÷ (4/1)-1= (1/10)-1 ÷ (1/4)= 10/1 ÷ 1/4= (10 ÷ 1/4)= (10 × 4)= 40.(ii) (4-1 + 8-1) ÷ (2/3)-1= (1/4 + 1/8) ÷ (3/2)= (2 + 1)/8 ÷ 3/2= (3/8 ÷ 3/2)= (3/8 ÷ 2/3)= 1/4 |
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