1.

Solve the previous problem for the cases of an isochoric, an isobaric and an isothermic process.

Answer»

Solution :For an isochoric process
`S_2 - S_1 = m/M C_(MV) in (T_2)/(T_1)`
For an isobaric process,
`S_2 - S_1 m/M C_(MP) ln (T_2)/(T_1)`.
For an isothermal process
`S_2 - S_1 = m/M R ln (V_2)/(V_1)`.


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