Saved Bookmarks
| 1. |
Solve the previous problem for the cases of an isochoric, an isobaric and an isothermic process. |
|
Answer» Solution :For an isochoric process `S_2 - S_1 = m/M C_(MV) in (T_2)/(T_1)` For an isobaric process, `S_2 - S_1 m/M C_(MP) ln (T_2)/(T_1)`. For an isothermal process `S_2 - S_1 = m/M R ln (V_2)/(V_1)`. |
|