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Solve the simultaneous equations 4 x + 5 y = − 19 6 x − 3 y = 24 Help this is urgent!!!! |
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Answer» 4x + 5y = −19 -----> eq1 6x − 3y = 24 -------> eq2 eq1 × 3 and eq2 × 5 12x + 15y = -57 ---> eq3 add both eq3 and eq4 12x + 18x = 63 30x = 63 x = 21/10 x value in eq1 or eq2 4x + 5y = −19 4(21/10) + 5y = -19 84 + 50y = -190 50y = -190 - 84 y = -274/50 check: substitute x and y value in eq1 or eq2 4x + 5y = −19 4(21/10) + 5(-274/50) = -19 (84 - 274) / 10 = -19 -190/10 = -19 -19 = -19 LHS = RHS Happy to help youAdd my answer to Brainliestand Follow me |
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