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Solve this 3(2y-3)-5 (y-1) |
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Answer» Answer: How to solve your QUESTION Your question is 3(2−3)−5(−1) 3(2y-3)-5(y-1)3(2y−3)−5(y−1) Simplify 1 Distribute 3(2−3)−5(−1) {\color{#c92786}{3(2y-3)}}-5(y-1)3(2y−3)−5(y−1) 6−9−5(−1) {\color{#c92786}{6y-9}}-5(y-1)6y−9−5(y−1) 2 Distribute 6−9−5(−1) 6y-9{\color{#c92786}{-5(y-1)}}6y−9−5(y−1) 6−9−5+5 6y-9{\color{#c92786}{-5y+5}}6y−9−5y+5 3 Add the numbers 6−9−5+5 6y{\color{#c92786}{-9}}-5y+{\color{#c92786}{5}}6y−9−5y+5 6−4−5 6y{\color{#c92786}{-4}}-5y6y−4−5y 4 Combine LIKE terms 6−4−5 {\color{#c92786}{6y}}-4{\color{#c92786}{-5y}}6y−4−5y 1−4 {\color{#c92786}{1Y}}-41y−4 5 Multiply by 1 1−4 1y-41y−4 −4 y-4y−4 Solution −4 Step-by-step explanation: PLEASE follow me |
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