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Solve this please fast |
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Answer» II) yes ,∆ABD=~∆CBD in ∆ABD and∆CBD AD=CD (given) AB=CB(given) BD =BD (coman) by SSS Crite area ∆ABD=~∆CBD iii) yes BD BISECT the /_ABC by above congruent rule ANGLE ABD and angle CBD are equal and both angle from the lineBD are equal hence it is bisector |
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