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Solve this question I will mark you as the brainlist I promise​

Answer»

Step-by-step explanation:

let the point at right angle be O

in triangle AOB ....AB= 13 ( by Pythagoras theorem)

area of triangle AOB= 1/2*Base*height

= 30 sq cm

Now..in triangle ABC , AB (a)= 13..BC(b)= 14 &

CD (c)=15

Semi-perimeter(s)= a+ b + c by 2

=21 cm

By herons formula,

area of ABC = √ s(s-a)(s-b)(s-c)

= √21 (21 -13) (21 -14 )(21- 15)

=√21*8*7*6

=√ 7056 cm ^ 2

= 84 cm^ 2

therefore the area of SHADED region

= AR (ABC )-ar (AOB)

=84-30

= 54 cm ^2

plzz mark me as brainlest..


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