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Solve : using the '%' in a .bat file as a literal?

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Hi all,

I am trying to use a '% ' as a literal in a .bat FILE.
As an example I want to runa .bat file with the following command;
2300%20West
The "%20 is the delimiter and I want it to run as a delimiter, but when run in a .bat file, it is DISPLAYED as ;
23000West
is it possible to TREAT the '%20' as a literal ?
any HELP would be greatly appreciated

RbakerjpqCode: [Select]2300%%20West
To sum up, double up the % signs in a BATCH to make them literal



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