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Solve with due regard to significant Jigures. (i) 46.7- 10.4 = (ii) (3.0xx10^(-8))+(4.5xx10^(-6))= |
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Answer» Solution :i) 46.7- 10.04 Here 46.7 has one DECIMAL place, and 10.04 has TWO decimal PLACES. `:. 46.7-10.04 = 36.66` The RESULT should have only one decimal place. The result is 36.7. `(II) 3.0xx10^(-8) +4.5xx10^(-6)` `= 0.03xx10^(-6)+4.5xx10^(-6)` `= 4.53xx10^(-6)` Here `4.5xx10^(-6)` has only one decimal place and 0.03x 10 can have two decimal places. This result should be rounded off to one decimalplace. `:. (3.0xx10^(-8))+(4.5xx10^(-6))=4.6xx10^(-6)` |
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