Solve without calculating the cubes and state the property to use. -i-

1.	Solve without calculating the cubes and state the property to use. -i- (-12)³+(7)³+(5)³ ii- (28)³+(-15)³+(13)³
Answer» Answer: i)-1260 ii)16380 Step-by-step explanation: LET's MOVE to some basic concepts of expansion, we have learnt that if a+b+c=0, then a^3+b^3+c^3=3abc. in (i), let a=-12, b=7, c=5 a+b+c =0 in this CASE, and hence, (-12)^3+(7)^3+(5)^3=3(-12)(7)(5)=-1260. in (ii), let a=28 b=-15, c=-13 a+b+c=0 in this case, and hence, (28)^3+(-15)^3+(-13)^3=3(-13)(-15)(28)=16,380. Please Mark as Brainliest

Solve without calculating the cubes and state the property to use. -i- (-12)³+(7)³+(5)³ ii- (28)³+(-15)³+(13)³

Answer»

Answer:

i)-1260 ii)16380

Step-by-step explanation:

LET's MOVE to some basic concepts of expansion,

we have learnt that if a+b+c=0, then a^3+b^3+c^3=3abc.

in (i),

let a=-12,

b=7,

c=5

a+b+c =0 in this CASE,

and hence, (-12)^3+(7)^3+(5)^3=3(-12)(7)(5)=-1260.

in (ii),

let a=28

b=-15,

c=-13

a+b+c=0 in this case,

and hence, (28)^3+(-15)^3+(-13)^3=3(-13)(-15)(28)=16,380.

Please Mark as Brainliest