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Solve: |x – 1| ≤ 5, |x| ≥ 2

Answer»

|x – 1| ≤ 5 and |x| ≥ 2 

⇒ -5 ≤ x – 1 ≤ 5 and x ≤ -2 (or) x > 2 

⇒ – 5 + 1 ≤ x ≤ 5 + 1 

⇒ -4 ≤ x ≤ 6 and x ≤ -2 (or) x ≥ 2 

Hence x < [-4, -2] ∪ [2, 6]



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