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Solve(x+2)(x+3)-(x+2)(x-3)=0 please solve this problem |
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Answer» Step-by-step explanation:(x+2)(x+3)-(x+2)(x-3)=0(x^2 +3x+2x+6)-(x^2 -3x+2x-6)=0x^2 +5x+6- x^2 +x +6=06x+12=06x= -12x= -12/6x= -2OR(x+2)(x+3)-(x+2)(x-3)=0(x+2)[(x+3)-(x-3)]=0(x+2)[x+3-x+3]=0(x+2)(6)=0(x+2)=0/6 = 0x+2 =0x=-2 |
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