Saved Bookmarks
| 1. |
Solve x dy/dx + y = xy^3 |
|
Answer» the CHANGE of VARIABLE y=1z we have the NEW versiondydx+y−xy3=0→x−z2+zz'z3=0 orx−z2+zz'=0Now CALLING ξ=z2 we havex−ξ+12ξ'=0Solving for ξ we OBTAIN easilyξ=12+x+Ce2x=z2 thenz=±√12+x+Ce2x=1y then finallyy=±1√12+x+Ce2x |
|