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Solve `(x-y^(2)x)dx=(y-x^(2)y)dy`. |
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Answer» Correct Answer - `(x^(2)-1)=C(y^(2)-1)` We have `x(1-y^(2))dx=y(1-x^(2))dy` `therefore (2x)/(x^(2)-1)dx=(2y)/(y^(2)-1)dy` Integrating both sides, we get `log_(e)(x^(2)-1)=log_(e)(y^(2)-1)log_(e)C` `therefore (x^(2)-1)=C(y^(2)-1)` |
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