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Solve `(xsiny/x)dy=(ysiny/x-x)dx`. |
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Answer» `(siny/x)(dy)/(dx) = (y/x.siny/x-1)` Put `y=vx` `rArr sinv(v+x(dv)/(dx))=(vsinv-1)` or `sinv(xdv)/(dx) =-1` or `intsinvdv=-int(dx)/(x)` `rArr cosv=log_(e)x+c` `rArr cosy/x=log_(e )x+c` |
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