1.

Some current should be passed for 2 hours to liberated 0.504 gm H_(2) gas. For same time if same current is passed then how much gram of oxygen is liberated ?

Answer»

2.0 gm
0.4 gm
4.0 gm
8.0 gm

Solution :`2H^(+)+2E^(-) to H_(2(g))` (reduction)
To liberated 2 gm `H_(2)` required CURRENT=`2xx96500C`
So, to liberate `0.504gm` `H_(2)` gas required current=(?)
`=(2xx96500)/(2)xx0.504F=48636C`
`4OH^(-) to 2H_(2)O+O_(2)+4e^(-)`
On passing `4xx96500` current 1 mole `O_(2)=32GM`
So, on passing 48636 C current=? `O_(2)`
`=(32xx48646)/(4xx96500)=4.032gm~~4.0gm`


Discussion

No Comment Found

Related InterviewSolutions