1.

Some energy levels of a molecule are shown the figure. The ratio of the wavelength r=(lamda_(1))/(lamda_(2)) is given by …………..

Answer»

`r=(3)/(4)`
`r=(1)/(3)`
`r=(4)/(3)`
`r=(2)/(3)`

Solution :`-E-(-2E)=(HC)/(lamda_(1))`
`:.E=(hc)/(lamda_(1))""......(1)`
and `-E-(-(4)/(3)E)=(hc)/(lamda_(2))`
`:.(E)/(3)=(hc)/(lamda_(2))""......(2)`
DIVIDING equation (2) by equation (1).
`(1)/(3)=(lamda_(1))/(lamda_(2))`
`:.(1)/(3)=r`


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