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Some properties as boiling point, freezing point and vapour pressure of a pure solvent change when solute molecules are added to get homogeneous solution. These are called colligative properties. Applications of colligative properties are useful in day-to day life. Its example is the use of ethylene glycol and water mixture as anti-freezing liquid in the radiator of automobiles. A solution M is prepared by mixing ethanol and water. The mole fraction of ethanol in the mixture is 0.9. Given : Freezing point depression constant of water (K_(f)^("water"))=1.86" K kg mol"^(-1) Freezing point depression constant of ethanol(K_(f)^("ethanol"))=2.0"K kg mol"^(-1) Boiling point elevation of water (K_(b)^("water"))=0.52" K kg mol"^(-1) Boiling point elevation constant of ethanol (K_(b)^("ethanol"))=1.2" K kg mol"^(-1) Standard freezing point of water = 273 K Standard freezing point of ethanol = 155.7 K Standard boiling point of water = 373 K Standard boiling point of ethanol = 251.5 K Vapour pressure of pure water = 32.8 mm Hg Vapour pressure of pure ethanol = 40 mm Hg Molecular weight of water = 18 g mol^(-1) Molecular weight of ethanol = 46 g mol^(-1) In answering the following questions, consider the solutions to be ideal dilute solutions and solutes to be non-volatile and non-dissociative. The freezing point of the solution M is

Answer»

268.7 K
268.5 K
234.2 K
150.9 K

Solution :Solution is `H_(2)O` and solvent is `C_(2)H_(5)OH`
`{:("let 0.9 MOLES of ethanol","0.1 mole of " H_(2)O),(41.4 gm,1.8 gm):}`
`Delta T_(F)=K_(f)xx M`
`Delta T_(f)=2XX[(1.8xx1000)/(1.8xx41.4)]`
`Delta T_(f)=4.83`
`T_(f)=155.7-4.83=150.9 K`


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