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Some solid NH_(4)HS is placed in a flask containing 0.5 atm of NH_(3), what would be pressure of NH_(3)and H_(2)S when equilibrium is reached NH_(4)HS_((g))hArrNH_(3(g))+H_(2)S_((g)),K_(p)=0.11 |
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Answer» `6.65` ATM `0.5+X x` `(0.5+x)=0.11` |
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