1.

Some solid NH_(4)HS is placed in a flask containing 0.5 atm of NH_(3), what would be pressure of NH_(3)and H_(2)S when equilibrium is reached NH_(4)HS_((g))hArrNH_(3(g))+H_(2)S_((g)),K_(p)=0.11

Answer»

`6.65` ATM
`0.665` atm
`0.0665` atm
`66.5` atm

Solution :`NH_(4)HShArrNH_(3)+H_(2)S`
`0.5+X x`
`(0.5+x)=0.11`


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