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Some springs are combined in series and parallel arrangement as shown in the figure and a mass m is suspended from them. The ratio of their frequencies will be :- A. `1:1`B. `2:1`C. `sqrt(3):2`D. `4:1` |
Answer» Correct Answer - C For `1^(st)` condition `k_(eff) = k/2` For `2^(nd)` condition `k_(eff) = ((2k)(k))/(2k+k) = 2/3k` `:. T = 2pisqrt((m)/(k)) :. f = 1/T = 1/2pi sqrt((k)/(m))` `(f_(1))/(f_(2)) = sqrt((k//2)/(2k//3)) = (sqrt(3))/(2)` |
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