InterviewSolution
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InterviewSolution
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Some times a reacant undergoes chemical/radioactive changes following two or more different paths to yield two or more different produces respectively. Such reactions are called parallel path reactions. If `K_(1)` and `K_(2)` are rate constans for the reaction of `A` follwing two parallel paths, then Then `K_(av) = K_(1) + K_(2)` For if `E_(1)` and `E_(2)` are energy fo activations, thenA. `E_("Total") = E_(1) + E_(2)`B. `E_("Total") = E_(1) - E_(2)`C. `E_("Total") = K_(1) E_(1) + K_(2)E_(2)`D. `E_("Total") = (K_(1) E_(1) + K_(2)E_(2))/(K_(1) + K_(2))` |
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Answer» Correct Answer - `d` `K_(av) = K_(1) + K_(2)` `A_(T)e^(-E_(T)//RT^(2)) = A_(1) e^(-E_(1)//RT^(2)) + A_(2) e^(-E_(2)//RT^(2))` ....(1) Differentiating eqn. (1) `A_(T). (E_(T))/(RT).e^(-E_(T)//RT^(2)) = A_(1). (E_(1))/(RT).e^(-E_(1)//RT^(2)) + A_(2) (E_(2))/(RT) e^(-E_(2)//RT^(2))` `K_(av) (E_(T))/(RT) = (K_(1)E_(1))/(RT) + (K_(2) E_(2))/(RT)` `(K_(1) + K_(2)) (E_(T))/(RT) = (K_(1)E_(1))/(RT) + (K_(2) E_(2))/(RT)` `:. E_(T) = (K_(1) E_(1) + K_(2) E_(2))/(K_(1) + K_(2))` |
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