1.

Someof the equipotential surfaces of the magnetic scalar potential the magnitude of magnetic field B at a point in the region is

Answer»

`10^(-3) T`
`(2)/sqrt(3)xx10^(-4)T`
`2xx10^(-4)` T
`sqrt(3)/(2)xx10^(-4)T`

SOLUTION :Field B will be normal to the EQUIPOTENTIAL lines THUS angle between field and x axis is `60^(@)` or `120^(@)`
Now `B=(DV)/(dr)`
Even for `theta=120^(@)`the magnitude of fieldis same


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