1.

Specific conductivity of 0.1 M NaCl aqueous solution is 1.06xx10^(-2)ohm^(-1)cm^(-1), then what is its molar conductivity in ohm^(-1)cm^(2)mol^(-1) ?

Answer»

`1.06xx10^(2)`
`1.06xx10^(3)`
`1.06xx10^(4)`
53

Solution :`Lamda_(m)=(Kxx1000)/(M)=(1.06xx10xx^(-2)xx1000)/(0.1)`
`=1.06xx10^(2)ohm^(-1)cm^(2)mol^(-1)`.


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