1.

Specific rotation of suguar solution is 0.5 deg m^(2)//kg.200 kgm^(-3) of impure sugar solution is taken in a sample polarimeter tube of length 20 cm and optical rotation is found to be 19^(@). The percentage of purity of sugar is

Answer»

`20%`
`80%`
`95%`
`89%`

Solution :`S_(lambda)`, the specific rotation of sugar solution `=THETA//l.C`
`theta = 19^(@), l=20 cm`,
`S_(lambda)=0.5 "deg"(m^(2))/(KG)=5 "deg"(cm^(2))/(g)`
`rArr C=(theta)/(lS_(lambda))=(19^(@))/(20xx5)=0.19 g//cm^(3)=19%`.
The concentration of the solution take
`= 200 kg//m^(3)=0.2 g//cm^(3)=20%`
`THEREFORE` The solution taken is 19 % pure `~= 20%`
This is pure (with 1 % error).


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