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Specific volume of cylindrical virus particle is 6.02×10-2 cc/gm whose radius and length are 7A^° and 10A^° respectively. If NA=6.02 x 1023find molecular weight of virus.

Answer» Specific volume of cylindrical virus particle is 6.02×10-2 cc/gm whose radius and length are 7A^° and 10A^° respectively. If NA=6.02 x 1023find molecular weight of virus.


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