1.

Speed of a solid sphere after rolling down an inclined plane is :

Answer»

`((10)/(7)gh)^(1//2)`
`sqrt((6)/(5)gh)`
`sqrt((4)/(5)gh)`
`(gh)^(1//2)`

Solution :TOTAL K.E. of rolling SPHERE `=(7)/(10)mv^(2)`
`THEREFORE (7)/(10)mv^(2)=mgh""v=sqrt((10)/(7)gh)`


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