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Speeds of two indentical cars are u and 4u at a specific instant. The ratio of the respective distances in which the two cars are stopped from that instant is : |
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Answer» `1:1` `S=(1/2mv^2)/(mu MG)=(v^2)/(2mug)` Here,`(S_(1))/(S_2)=(u^2)/((4u)^2)=(1)/(16)`. |
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