1.

Speeds of two indentical cars are u and 4u at a specific instant. The ratio of the respective distances in which the two cars are stopped from that instant is :

Answer»

`1:1`
`1:4`
`1:8`
`1:16`

SOLUTION :Stopping distance=`(K.E.)/("Force of resistance")`
`S=(1/2mv^2)/(mu MG)=(v^2)/(2mug)`
Here,`(S_(1))/(S_2)=(u^2)/((4u)^2)=(1)/(16)`.


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