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Spheres of iron and lead having same mass are completely immersed in water. Density of lead is more than that of iron. Apparent loss of weight is W_(1) for iron sphere and W_(2) for lead sphere. Then (W_(1))/(W_(2)) is : |
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Answer» 1 `m_(1)=m_(2)` `V_(1)p_(1)=V_(2)p_(2)` `(V_(1))/(V_(2))=(p_(2))/(p_(1))rArrprop1/p` Since density of iron is less than density of lead. `therefore` Iron sphere has more volume and will displace more water. Now apparent loss of weight is equal to weight of water displaced. So apparent loss of weight `W_(1)` for iron is more than loss of wt. `W_(2)` for lead. `therefore(W_(1))/(W_(2))gt1` So correct CHOICE is (d). |
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