Split the reaction 2K(s) + Cl2 (g) → 2KCl (s) into oxidation and red – InterviewSolution

InterviewSolution

1.

Split the reaction 2K(s) + Cl2 (g) → 2KCl (s) into oxidation and reduction half reactions.

Answer»

\(2\overset{o}{K}(s) +\overset{o}{Cl}(g)\rightarrow2\overset{+1}{K}\overset{-1}{C}(s)\)

Oxidation half reaction

K → K⁺ + e^- (Loss electron)

Reduction half reaction

Cl₂ + 2e^- → 2Cl^- (Gain electron)

Discussion

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