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Spotting a police car ahead, the driver of the car in the previous example slows from 32 m//s to 20 m//s in 2 sec. Find the car's average acceleration. |
| Answer» Solution :Dividing the change in velocity `(20 m//s -32 m//s = - 12 m//s)` by the time interval during which the change OCCURRED (2 s) gives us ` overline(a) = Delta V // Delta t = (-12 m//s) // (2 s)= -6 m//s^(2)`. The negative sign MEANS that the DIRECTION of the acceleration is opposite the direction of the velocity. The CAR is slowing down. | |