\sqrt{3 + \sqrt{2 = x \: then \: \sqrt{3 - \sqrt{2 = } } } }3+2=xthen3

1.	\sqrt{3 + \sqrt{2 = x \: then \: \sqrt{3 - \sqrt{2 = } } } }3+2=xthen3−2=
Answer» ANSWER: \SQRT{3 + \sqrt{2 = X \: then \: \sqrt{3 - \sqrt{2 = } } } }3+2=xthen3−2=

\sqrt{3 + \sqrt{2 = x \: then \: \sqrt{3 - \sqrt{2 = } } } }3+2=xthen3−2=

Answer»

ANSWER:

\SQRT{3 + \sqrt{2 = X \: then \: \sqrt{3 - \sqrt{2 = } } } }3+2=xthen3−2=

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\sqrt{3 + \sqrt{2 = x \: then \: \sqrt{3 - \sqrt{2 = } } } }3+2=xthen3−2=​​​​​

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\sqrt{3 + \sqrt{2 = x \: then \: \sqrt{3 - \sqrt{2 = } } } }3+2=xthen3−2=