1.

Square root of 1 minus sign Tita by 1 +sin tita is equal to secant tita - tan tita. prove​

Answer»

L.H.S√[ (1 - Sin∆) / (1 + Sin∆) ]= √[ (1 - Sin∆) × (1 - Sin∆) / (1 + Sin∆) × (1 - Sin∆) ]= √[ (1 - Sin∆)^2 / (1^2 - Sin^2∆) ]= √[ (1 - Sin∆)^2 / Cos^2∆ ]= (1 - Sin∆) / (Cos∆)= (1/Cos∆) - (Sin∆ / Cos∆)= Sec∆ - Tan∆ = R.H.S (PROVED)


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