1.

SRP of Sn^(2+)//Sn^(4+) is 0.5 , SRP of Au//Au^(3+) is 1.5, give reaction for the cell

Answer»

`2Sn^(2+)+3Au^(3+) to 2Sn^(4+)+3Au`
`3Sn^(2+)+2Au^(3+) to 3Sn^(4+)+2Au`
`2Sn^(4+)+3Au to 2Sn^(2+) +3Au^(3+)`
`3Sn^(4+)+2Au to 3Sn^(2+)+2Au^(3+)`

Solution :SRP of `Au//Au^(3+) gt` SRP of `Sn^(2+)//Sn^(4+)`.
THEREFORE `Au^(+3)` undergo reduction and `Sn^(2+)` undergo OXIDATION.


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