1.

Stable oxidation state of Yb is

Answer»

`+2`
`+3`
`+4`
`+6`

Solution :We know that, Yb shwo +2 and +3 oxidation STATE. `Yb ^(2+)` has electronic configuration `6s^(0), 4F^(14), 5d^(0) and Yb^(3+)` heas electronic configuration `6s^(0), 4f^(13), 5d^(0).` According to HUND's RULE `4f^(14)` configuration is more stable. HENCE Yb shows `+2` stable oxidation state.


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