1.

Standard electrode potential data are useful for understanding the suitability of an oxidant in a redox titration. Some half cell reaction and their standard potentials are given below MnO_(4)^(-)(aq)+8H^(+)(aq)+5e^(-)toMn^(2+)(aq)+4H_(2)O(l)""E^(@)=1.51V Cr_(2)O_(7)^(2-)(aq)+14H^(+)(aq)+6e^(-)to2Cr^(3+)(aq)+7H_(2)O(l)""E^(@)=1.38V Fe^(3+)(aq)+e^(-)toFe^(2+)(aq)""E^(@)=0.77V Cl_(2)(g)+2e^(-)to2Cl^(-)(aq)""E^(@)=1.40V Identify the only incorrect statement regarding the quantitative estimation of aqueous Fe(NO_(3))_(2)

Answer»

`MnO_(4)^(-)` can be used in aqueous HCl
`Cr_(2)O_(7)^(2-)` can be used in aqueous HCl
`MnO_(4)^(-)` can be used in aqueous `H_(2)SO_(4)`
`Cr_(2)O_(7)^(2-)` can be used in aqueous `H_(2)SO_(4)`

Solution :`MnO_(4)^(-)` will oxidize `Cl^-` ION ACCORDING to the equation,
`2MnO_(4)^(-)+16H^(+)+10Cl^(-)to2Mn^(2+)+8H_(2)O+5Cl_(2)uarr` The cell corresponding to this reaction is as follows:
`Pt,Cl_(2)("1 ATM")|Cl^(-)||MnO_(4)^(-), Mn^(2+),H^(+)|Pt,`
`E_(cell)^(o)=1.51-1.40=0.11V`
`E_(cell)^(o)` BRING +ve, `DeltaG^(o)` will be -ve and hence the above reaction is feasible. `MnO_(4)^(-)` will not only oxidize `Fe^(2+)` ion but also `Cl^(-)` ion simultaneously.


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