1.

Standard electrode potentials are Fe^(2+)//Fe,""E^(@)=-0.44V Fe^(3+)//Fe^(2),""E^(@)=+0.77V Fe^(2+),Fe^(3+) and Fe blocks are kept together, then

Answer»

`Fe^(3+)` increases
`Fe^(3+)` decreases
`Fe^(2+)//Fe^(3+)` remains unchanged
`Fe^(2+)` decreases

Solution :For the emf to be +ve, the following half-cell REACTIONS will occur.
`FetoFe^(2+)+2e^(-),E^(@)=+0.44V`
`underline(2Fe^(3+)+2e^(-)2Fe^(2+),""E^(@)=+0.77V" ")`
OVERALL reaction:
`Fe+2Fe^(3+)to3Fe^(2+),""E_(cell)^(@)=0.121V`
Thus, `Fe^(3+)` will DECREASE.


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