1.

Standard emf of 0.59 V of galvanic cell in which 3 mole electron taking part in redox reaction. So for such reaction find out value of equilibrium constant ?

Answer»

`10^(25)`
`10^(20)`
`10^(15)`
`10^(30)`

Solution :`LOGK=(nE_(CELL)^(@))/(0.059)=(3xx0.59)/(0.59)=30`
`therefore K=10^(30)`.


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