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Standard enthalpy of vaporisation`DeltaV_(vap).H^(Theta)` for water at `100^(@)C`is`40.66kJmol^(-1)`.The internal energy of Vaporization of water at` 100^(@)C("in kJ mol"^(-1))`isA. `+37.56`B. `-43.76`C. `+43.76`D. `40.66` |
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Answer» Correct Answer - A `DeltaH_(vap)^(@)=40.66 kJ mol^(-1)` `T=273+100=373 K`, `DeltaU=?` `DeltaH=DeltaU+Deltan_(g) RT `or `DeltaU=DeltaH-Deltan_(g)RT` `Deltan_(1)(g)=1-0=1` `:. DeltaU=40.66 kJ mol^(-1)-1xx8.314xx10^(-8)JK^(-1)mol^(-1)xx373 K` `=(40.66-3.101) kJ mol^(-1)` `=37.559 kJ mol^(-1)` |
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