Standard entropy of `X_(2)` , `Y_(2)` and `XY_(3)` are `60, 40 ` and `50JK^(-1)mol^(-1)` , respectively. For the reaction, `(1)/(2)X_(2)+(3)/(2)Y_(2)rarrXY_(3),DeltaH=-30KJ` , to be at equilibrium, the temperature will be:A. `1250 K`B. `500 K`C. `750 K`D. `1000 K`

Standard entropy of `X_(2)` , `Y_(2)` and `XY_(3)` are `60, 40 ` and `

1.	Standard entropy of `X_(2)` , `Y_(2)` and `XY_(3)` are `60, 40 ` and `50JK^(-1)mol^(-1)` , respectively. For the reaction, `(1)/(2)X_(2)+(3)/(2)Y_(2)rarrXY_(3),DeltaH=-30KJ` , to be at equilibrium, the temperature will be:A. `1250 K`B. `500 K`C. `750 K`D. `1000 K`
Answer» Correct Answer - c `1/2X_(2)+3/2Y_(2)toXY_(3)` `DeltaS_("reaction")=50-(3/2xx40+1/2xx60)` `=-40 J mol^(-1), DeltaG=DeltaH-TDeltaS` at equilibrium , `DeltaG=0` `DeltaH=TDeltaS` `30xx10^(3)=Txx40, :. T=750 K`

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Standard entropy of `X_(2)` , `Y_(2)` and `XY_(3)` are `60, 40 ` and `50JK^(-1)mol^(-1)` , respectively. For the reaction, `(1)/(2)X_(2)+(3)/(2)Y_(2)rarrXY_(3),DeltaH=-30KJ` , to be at equilibrium, the temperature will be:A. `1250 K`B. `500 K`C. `750 K`D. `1000 K`

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