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InterviewSolution
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Standard heat of formation of `CH_(4)(g), CO_(2)(g)` and `H_(2)O(l)` are -75, -393.5, -286 kJ respectively. Find out the change in enthalpy for the reaction. `CH_(4)(g)+2O_(2)(g)rarr CO_(2)(g)+2H_(2)O(l)` |
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Answer» `CH_(4)(g)+2O_(2)(g)rarr CO_(2)(g)+2H_(2)O(l)` `Delta H_("of reaction")=[Sigma Delta H_(f)^(@)" of product" - Sigma Delta H_(f)^(@)" of reactant"]` `Delta H^(@)[(-393.5)+2(-286)]-[(-75)+2(0)]` `Delta H^(@)=(-965.5)-(-75)=-890.5 kJ` |
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