1.

Standard reduction potential of following reactions is given below : Mn^(2+)+2e^(-) to Mn","E^(o)=-1.18V and Mn^(3+)+e^(-) to Mn^(2+),""E^(o)=1.51V, then what is the redox potential of reaction Mn^(3+)+3e^(-) to Mn ?

Answer»

`0.33V`
`1.69V`
`-0.28V`
`-0.85V`

Solution :(i) `MN^(2+)+2E^(-) to Mn` (reduction)
`DeltaG^(@)=-nFE^(@)=2.36F`. . . (1)
(II) `Mn^(3+)+e^(-) to Mn^(2+)` (reduction)
`DeltaG^(@)=-nFE^(@)=--1.51F` . . . (2)
Sum of equation (1) and (2),
(iii) `Mn^(3+)+3e^(-) to Mn` (reduction)
`DeltaG^(@)=2.36F+(-1.51F)`
`=0.85F`
`DeltaG^(@)=-nFE^(@)`
`THEREFORE 0.85F=-3xxFxxE^(@)`
`therefore E^(@)=(0.85)/(3)=-0.28V`


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