1.

Standard reduction potential of half-cells are given as follows : Zn^(2+)+2e^(-) to Zn,E^(o)=-0.76V Fe^(2+)+2e^(-) to Fe,E^(o)=-0.44V What is the emf of following reactions ? Zn_((S))+Fe_((aq))^(2+) to Zn_((aq))^(+2)+Fe_((S)).

Answer»

`-1.20V`
`+1.20V`
`+0.32V`
`-0.32V`

Solution :`E_(CELL)^(o)=E_("Reduction (CATHODE)")^(o)-E_("Reduction (anode)")^(o)`
`=E_(FE^(2+)|Fe)^(o)-E_(Zn^(2+)|Zn)^(o)`
`=-0.44-(-0.76)`
`+0.32V`


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