1.

Standing waves are produced in a 10 m long stretched string. If the string vibrates in 5 segments and the wave velocity is 20 m/s, the frequency is :

Answer»

2 Hz
4 Hz
5 Hz
10 Hz

Solution :l = 10 m , DISTANCE between two NODES
`= (10)/(5) ` = 2M
`therefore (lambda)/(2) = 2m or lambda = 4m`
v = 20 `ms^(-1)`
`therefore n = (v)/(lambda)= (20)/(4) ` = 5 Hz.
CORRECT choice is (C).


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