1.

Starting from the origin a body osillates simple harmonicall with a period of 2 s. A fter what time will its kinetic energy be 75% of the total energy?A. `1/6s`B. `1/4s`C. `1/3s`D. `1/12s`

Answer» Correct Answer - A
`KE = (75/100)TE`
`rArr 1/2momega^(2)(A^(2) - x^(2)) = 3/4[1/2momega^(2)A^(2)] rArr x = (A)/(2)`
Now from `x = Asinomegat` we have
`A/2 = Asin(omegat) rArr ((2pi)/(T)) t = (pi)/(6) rArr t = 1/6s`


Discussion

No Comment Found

Related InterviewSolutions