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Starting from the origin a body osillates simple harmonicall with a period of 2 s. A fter what time will its kinetic energy be 75% of the total energy?A. (a) `1/6s`B. (b) `1/4s`C. (c )`1/3s`D. (d) `1/(12)s` |
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Answer» Correct Answer - A (a) K.E of a body undergoing SHM is given by, K.E.=1/2ma^(2)omega^(2) cos^(2) omegat, T.E.=1/2ma^(2)omega^(2)` Given K.E.=0.75T.E`. `rArr0.75=cos^(2)omegat rArromegat=(pi)/6` `rArrt=(pi)/(6xxomega)rArr t=(pixx2)/(6xx2pi)rArr t=1/6s` |
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