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Starting with the same initial conditions, an ideal gas expands from volume V_(1)" to "V_(2) in three different ways. The work done by the gas is W_(1) if the process is purely isothermal, W_(2) if purely isobaric and W_(3) if purely adiabatic. Then SS |
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Answer» `W_(2) gt W_(1) gt W_(3)` Since work DONE = area under P-V diagram.  `THEREFORE W_(2) gt W_(1) gt W_(3)` as area under curve 2 is maximum and that under curve 3 is minimum. `therefore` Correct choice is (a). |
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